2[w-(2w+3)+1]=2(w+2)

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Solution for 2[w-(2w+3)+1]=2(w+2) equation:


Simplifying
2[w + -1(2w + 3) + 1] = 2(w + 2)

Reorder the terms:
2[w + -1(3 + 2w) + 1] = 2(w + 2)
2[w + (3 * -1 + 2w * -1) + 1] = 2(w + 2)
2[w + (-3 + -2w) + 1] = 2(w + 2)

Reorder the terms:
2[-3 + 1 + w + -2w] = 2(w + 2)

Combine like terms: -3 + 1 = -2
2[-2 + w + -2w] = 2(w + 2)

Combine like terms: w + -2w = -1w
2[-2 + -1w] = 2(w + 2)
[-2 * 2 + -1w * 2] = 2(w + 2)
[-4 + -2w] = 2(w + 2)

Reorder the terms:
-4 + -2w = 2(2 + w)
-4 + -2w = (2 * 2 + w * 2)
-4 + -2w = (4 + 2w)

Solving
-4 + -2w = 4 + 2w

Solving for variable 'w'.

Move all terms containing w to the left, all other terms to the right.

Add '-2w' to each side of the equation.
-4 + -2w + -2w = 4 + 2w + -2w

Combine like terms: -2w + -2w = -4w
-4 + -4w = 4 + 2w + -2w

Combine like terms: 2w + -2w = 0
-4 + -4w = 4 + 0
-4 + -4w = 4

Add '4' to each side of the equation.
-4 + 4 + -4w = 4 + 4

Combine like terms: -4 + 4 = 0
0 + -4w = 4 + 4
-4w = 4 + 4

Combine like terms: 4 + 4 = 8
-4w = 8

Divide each side by '-4'.
w = -2

Simplifying
w = -2

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